If you have a gas sample with an initial pressure of 16 atm, an initial volume of 20 L and a temperature of 500 K, what will the final temperature be if you change the pressure to 4 atm and the volume to 35 L?

T₂ = 218.75 K

Explanation:

Given data:

Initial volume = 20 L

Initial pressure = 16 atm

Initial temperature = 500 K

Final temperature = ?

Final volume = 35 L

Final pressure = 4 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

P₁V₁/T₁ = P₂V₂/T₂  

T₂  = P₂V₂ T₁/ P₁V₁

T₂ = 4 atm × 35 L × 500 K / 16 atm × 20 L  

T₂ = 70000 atm .L. K / 320 atm.L

T₂ = 218.75 K

the temperature of the gas, in k, not celsius.