If you were balancing an equation containing the O2 molecule, which of the following would be correct representations of O2 and its coefficient? a. ½O2
b. O2
c. 3O2
d. 6O2
e. 3O
f. 5O3

a. ½O2

b. O2

c. 3O2

d. 6O2

Explanation:

Hello!

In this case, since balancing chemical reactions can be attained by adding coefficients prior to each species in the chemical equation, we infer that the following representations are correct because they have a coefficient and the molecule O2 as diatomic oxygen:

a. ½O2

b. O2

c. 3O2

d. 6O2

It means that e. and f. are wrong because even when they have the coefficient, the molecule O2 is not properly written.

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number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.