Plz help it's urgent

The number of moles left = 0.0067 moles

Further explanation

Given

0.28 g CO

2 x 10²¹ molecules removed

Required

Number of moles left

Solution

Initial mol of CO(MW=28 g/mol) :

mol = 0.28 : 28

mol = 0.01

The number of molecules in 0.01 mol :

= 0.01 x 6.02 x 10²³

= 6.02 x 10²¹

2 x 10²¹ molecules removed, so molecules left :

= 6.02 x 10²¹ - 2 x 10²¹

= 4.02 x 10²¹

moles of 4.02 x 10²¹ :

= 4.02 x 10²¹ : 6.02 x 10²³

= 0.0067 moles

The answer is c. 320 g

Since there is the same amount of agn03 in both silver chloride and silver nitrate they produce the same amount of moles. therefore silver chloride produces the same amount of silver nitrate, so your answer is 15.0 moles of silver nitrate. i hope this !