What volume, IN MILLILITERS, of 5.0M HCl solution is required to react with 3.00 g or magnesium metal?

The volume of HCl = 2.10⁴ mL

Given

5.0 M(mol/L) HCl solution

3 g of Mg

Required

Volume of HCl

Solution

Reaction

Mg + 2HCl ⇒ MgCl₂ + H₂

mol of Mg (Ar=24 g/mol) :

mol = mass : Ar

mol = 3 : 24

mol = 0.125

From the equation, mol ratio of Mg : HCl = 1 : 2, so mol HCl :

= 2/1 x mol Mg

= 2 x 0.125

= 0.25

Molarity : mol solute per liters solution

M = m x V

V = M : m

V = 5 mol/L : 0.25

V = 20 L = 2.10⁴ mL

your answer would be a. 12.5 kg

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