What is the percent composition of Cs in CsPO4?

58.3%

Explanation:

The formula of the compound is given as:

     CsPO₄  

Now, the percentage composition of Cs in the compound is = ?

So;

To find this parameter, find the molar mass of the compound:

  Molar mass of  CsPO₄   = 132.9 + 31 + 4(16)  = 227.9g/mol

Percentage composition of Cs=   = 58.3%

the formula mass of a molecule or a compound is the sum of the atomic weights of the atoms in its empirical formula

(that's what i know about formula mass)

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.