A potted plant is placed under a grow lamp, which provides 4,200 J of energy to the plant and the soil over the course of an hour. The specific heat capacity of the soil is about 0.84 J/g° C and there are about 2,400 g of soil. How much does the temperature of the soil increase?

Temperature increase = ΔT = 2.08 °C

Explanation:

Given data:

Energy absorbed by plant = 4200 J

Specific heat capacity of soil = 0.84 J/g°C

Mass of soil = 2400 g

How much temperature increase = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

by putting values,

4200 J = 2400 g ×0.84 J/g°C × ΔT

4200 J = 2016 J/°C  × ΔT

ΔT = 4200 J  / 2016 J/°C

ΔT = 2.08 °C

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.