How many moles of nitrogen gas will occupy a volume of .347 L at 6680 mmHg and 27°C?

0.124 mol- I think not completely positive on it

Explanation:6680⋅mm⋅Hg is not a realistic measurement of pressure

I assume you mean 6680⋅mm⋅Hg/760⋅mm⋅Hg⋅atm^-1 = 8.79⋅atm.

And we use the Ideal Gas Equation:

n=PV/RT=8.79⋅atm×0.347⋅L/0.0821⋅L⋅atm⋅K−1⋅mol−1×300⋅K=0.124⋅mol

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.