Determine the Oxidation number of the indicated element in each of the following substances: Mn in KMnO4 S in SO2 C in COCl2 P in PF4 O in K2O2

1. Mn = +7

2. S = +4

3. C = +4

4. P = +4

5. O = -1

Explanation:

The oxidation number of each element in a compound is as follows:

1. Mn in KMnO4

KMnO4 = 0

Where; K = +1, O = -2, Mn = x

+1 + x -2(4) = 0

1 + x - 8 = 0

x - 7 = 0

x = +7

2. S in SO2

SO2 = 0

Where; S = x, O = -2

x + -2(2) = 0

x - 4 = 0

x = +4

3. C in COCl2

COCl2 = 0

Where; C = x, O = -2, Cl = -1

x + -2 + -1(2) = 0

x + -2 + -2 = 0

x -2 - 2 = 0

x - 4 = 0

x = +4

4. P in PF4

PF4 = 0

Where; P = x, F = -1

x + -1 (4) = 0

x - 4 = 0

x = +4

5. O in K2O2

K2O2 = 0

Where; K = +1, O = x

+1(2) + x(2) = 0

2 + 2x = 0

-2x = 2

x = -1

petroleum? coal maybe?

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.