Pls helppp How many energy must be absorbed by 150.0 grams of water to raise it's temperature by 50.00°C?

The heat absorbed to raise temperature : Q = 31350 J

Given

m = mass = 150 g

Δt = Temperature difference : 50 °C

Required

Heat absorbed

Solution

Heat can be formulated

Q = m.c.Δt

The specific heat of water = c = 4.18 J/g °C  

Input the value :

Q = 150 x 4.18 x 50

Q = 31350 J

1.43 x 10^-11 j the guy commented the awnser just making sure u see it .