A sample of iron (III) chloride has a mass of 26.29g. How many moles would this be?

0.1621 mol FeCl₃

General Formulas and Concepts:

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Chemistry

Compounds

Determining compound formulas

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisExplanation:

Step 1: Define

26.29 g FeCl₃ (iron (III) chloride)

Step 2: Identify Conversions

Molar Mass of Fe - 55.85 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of FeCl₃ - 55.85 + 3(35.45) = 162.2 g/mol

Step 3: Convert

Set up:                              Multiply:                            

Step 4: Check

Follow sig fig rules and round. We are given 4 sig figs.

0.162084 mol FeCl₃ ≈ 0.1621 mol FeCl₃

What are the options? i can you if you give them.

You would do 1500/4 and the answer is 375