If you had excess chlorine, how many moles of of aluminum chloride could be produced from 11.0 g of aluminum

0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.

Explanation:

To calculate the moles :

According to stoichiometry :

is the limiting reagent as it limits the formation of product and is the excess reagent.

As 2 moles of give = 2 moles of

Thus moles of give =  of

Thus 0.407 moles of aluminum chloride could be produced from 11.0 g of aluminum.

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