How many grams are in 3.93 x 1024 molecules of CCl4?

Mass of CCl₄ = 1004.137 g

Given

3.93 x 10²⁴ molecules of CCl₄

Required

mass

Solution

1 mol = 6.02 x 10²³ particles(molecules, ions, atoms)

So mol of  CCl₄ :

n = N : No(No = Avogadro's number)

n = 3.93 x 10²⁴ : 6.02 x 10²³

n = 6.528

Mass of  CCl₄ (MW=153,82 g/mol) :

mass = mol x MW

mass = 6.528 x 153,82 g/mol

mass = 1004.137 g