What is the unit of measurement for temperature?
Solve for V2
290L/ 23C = V2/ 16C

V₂ = 283.15 L

Explanation:

The temperature must be in kelvin scale. We will convert the degree celsius into kelvin and then solve the equation for V₂.

T₁ = 23°C (23+273.15 = 296.15 K)

T₂ = 16°C (16+273.15 = 289.15 K)

Now we will calculate the value of V₂

290 L / 296.15 K = V₂ / 289.15 K

V₂ = 290 L × 289.15 K / 296.15 K

V₂ = 83853.5 L.K /296.15 K

V₂ = 283.15 L

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

i'm pretty sure it is letter c.) car