I NEED HELP ASAPPP PLZ

1. Heat needed = 293.25 J

2. Time to leave : 2 s

Given

1.5 g H2

Cp H2 = 14.27 g/J C

Δt= 13.7

Required

1. Heat needed

2. Fridge time

Solution

1. Heat can be formulated :

Q = m.c.Δt

Q = 1.5 x 14.27 x 13.7

Q = 293.25 J

2. Heat decreases = 150 J/s, so for 293.25 J :

d: the voltage of the secondary coil is less than that of the primary coil.

im not suree sorry if wrong