My teacher gives me a block of some unknown material. I weigh it and find out that it weighs 22.5g. I then heat it up using 2067J of energy and notice that it only changes by 25 degrees celsius. What is its specific heat?

The specific heat of unknown material : 3.675 J/g °C

Given

mass of block = 22.5 g

Q = heat = 2067 J

Δt=25 °C

Required

The specific heat

Solution

Heat can be formulated :

Q = m.c.Δt

Input the value :

2067 J = 22.5 g x c x 25 °C

c = 3.675 J/g °C

yes, water is wet, just as it makes other things wet, it is wet itself, kinda like ice, when ice is in water, the ice makes water cold, and ice is cold, therefore with that example, water is wet

i dont know

explanation: