Consider the production of sulfur trioxide from sulfur dioxide and oxygen gas:How many grams of sulfur dioxide reacted if 163 kilojoules of heat were evolved in an experiment

102.4 g

Explanation:

The equation of the reaction is;

2SO2(g) + O2(g) > 2SO3(g) ΔH = -198 KJ/mol

Now, given that;

If 2 moles of SO2 evolves 198 KJ/mol of heat

x moles of SO2 evolves 163 KJ/mol of heat

x = 2 * 163/198

x = 1.6 moles of SO2

molar mass of SO2 = 64 g/mol

mass of SO2 = 1.6 moles * 64 g/mol = 102.4 g

the answer is 303.15 or 303

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8