What mass of silver chloride can be produced from 1.01 L of a 0.196 M solution of silver nitrate? Express your answer with the appropriate units.

Mass of Silver chloride-AgCl =  28.314 g

Given

1.01 L of a 0.196 M solution of Silver nitrate

Required

Mass of Silver chloride

Solution

Reaction

AgNO₃ + NaCl ⇒ AgCl + NaNO₃

mol of AgNO₃ :

mol = M x V

mol = 0.196 x 1.01

mol = 0.198

From equation, mol ratio of AgNO₃ : AgCl = 1 : 1, so mol AgCl = 0.198

mass AgCl (MW=143 g/mol)  :

mass = mol x MW

mass = 0.198 x 143

mass = 28.314 g

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