4AI + 302 — 2Al2O3 In this reaction, how many grams of O2 are required to
completely react with 110 grams of Al?

Mass = 96 g

Explanation:

Given data:

Mass of oxygen required = ?

mass of Al = 110 g

Solution:

Chemical equation:

4Al + 3O₂     →     2Al₂O₃

Number of moles of Al:

Number of moles = mass/molar mass

Number of moles = 110 g/ 27 g/mol

Number of moles = 4 mol

Now we will compare the moles of Al and oxygen.

                     Al           :           O₂

                      4            :          3

Mass of oxygen:

Mass = number of moles × molar mass

Mass = 3 mol ×  32 g/mol

Mass = 96 g