What is the theoretical yield of aluminum that can be produced by the reaction of 60.0 g of aluminum oxide with 30.0 g of carbon according to the following chemical equation? ALLO, + 3C SH 2Al + 3CO a. 31.8 g
b. 30g
c. 101.2 g
d. 45 g
e. 7.9 g

31.8 g

Explanation:

To calculate the moles :

According to stoichiometry :

1 mole of require 3 moles of

Thus 0.59 moles of will require=  of

Thus is the limiting reagent as it limits the formation of product and is the excess reagent as it is present in more amount than required.

As 1 mole of give = 2 moles of

Thus 0.59 moles of give =  of

Mass of

Thus 31.8 g of will be produced from the given masses of both reactants.

the atomic number will stay the same no matter how many electrons it has, so it doesn’t decrease nor increase. it’ll only change with a different number of protons