What carpet Burns in a deficiency of O2 a mixture of CO and CO2 forms. Carbon Burns in excess O2 to form only CO2 and CO Burns in excess O2 to form only CO2. Calculate ΔH for C(graphite +1/2O2) →CO(g).

Explanation:

From the combustion of carbon, the reactions occurring in limited oxygen conditions are:

If it occurs in excess, then any leftover CO changes to CO2. i.e.

  ---- (1)

         ----- (2)

From (1), the enthalpy change is:

From (2), the enthalpy change is:

Subtracting (2) from (1), we get:

The enthalpy change ΔH of the reaction = -110.5 kJ/mol

it's filtration, but this is an assumption so my apologies if i got this