An 18.0 g piece of an unidentified metal was heated from 21.5 °C to 89.0 °C. If 789.75 J of heat energy was absorbed by the metal in the heating process, what was the identity of the metal?

The metal is Calcium.

Explanation:

To calculate the specific heat of substance during the reaction.

where,

q = heat absorbed = 789.75 J

c = specific heat of metal = ?

m = mass of substance = 18.0 g

= final temperature  - initial temperature  =

Now put all the given values in the above formula, we get:

As specific heat is characteristic of each metal and thus the metal is calcium which has  specific heat of

1. they vary with a higher number because boiling is way hotter than melting