If the rate constant of a reaction is 0.010 L/mols at 30 °C, calculate the rate constant at 100 °C assuming the rate doubles for each 10 °C rise in temperature. It says that the answer is 1.3 L/mols, but I don't understand why.

1.3L/mols

Explanation:

At 30°C the rate constant is 0.010L/mols

As the rate doubles for each 10° rise in temperature:

At 40°:

0.010L/mols*2 = 0.020L/mols

At 50°C:

0.020L/mols*2 = 0.040L/mols

At 60°C:

0.040L/mols*2 = 0.080L/mols

At 70°C:

0.080L/mols*2 = 0.160L/mols

At 80°C:

0.160L/mols*2 = 0.320L/mols

At 90°C:

0.320L/mols*2 = 0.640L/mols

And at 100°C:

0.640L/mols*2 =

1.280L/mols ≅

i think it is true since you can test the answer and can use observations to complete it.