What is the mass of a solution containing 0.2 molar of sodium chloride

Explanation:

The reaction is FeCl

3+3NaOH→Fe(OH) 3+3NaCl.

Thus, 1 mole of ferric chloride will react with 3 moles of NaOH to form one mole of ferric hydroxide.

0.24 moles of sodium hydroxide will react with 0.08 moles of ferric chloride to form 0.08 moles of ferric hydroxide.

The unreacted amount of ferric chloride is 0.2−0.08=0.12 moles.

In this reaction, sodium hydroxide is the limiting reagent.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o