When calculating the amount of product formed during alcohol fermentation, one mole of ethanol is chemically equivalent to what volume of CO2 (g) measured at 1 atm and 273 K

44.8 dm^3

Explanation:

The equation for the fermentation of glucose is;

C6H12O6 > 2C2H5OH + 2CO2

This means that two moles of ethanol carbon dioxide are produced.

If 1 mole of gas at STP occupies 22.4 dm^3, then two moles occupies; 22.4 dm^3 × 3 = 44.8 dm^3

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