The molar heat capacity is represented in the temp range 298 to 400 k by the emprical expression 14.73+0.1272 calculate the enthalpy if formation of ethane at 350 k from its valu at 298 k

Explanation:

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In this case, since the enthalpy of formation of ethane at 298 K is about -84 kJ/mol, via the Kirkoff's law, we can compute it a 350 K as shown below:

It means we can integrate to get:

Now, we can plug in the enthalpy of formation in consistent units to obtain:

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explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.