how many grams of zinc will be formed if 32 G of copper reacts with zinc nitrate copper 1 nitrate is the other product

Mass = 32.69 g

Explanation:

Given data:

Mass of copper = 32 g

Mass of zinc formed = ?

Solution:

Chemical equation:

Cu + Zn(NO₃)₂     →       Cu(NO₃)₂ + Zn

Number of moles of copper:

Number of moles = mass/molar mass

Number of moles = 32 g/ 63.55 g/mol

Number of moles = 0.5 mol

now we will compare the moles of zinc with copper.

           Cu          :           Zn

            1            :            1

          0.5          :         0.5

Mass of Zn:

Mass = number of moles × molar mass

Mass = 0.5 mol  × 65.38 g/mol

Mass = 32.69 g

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