Describe how you would prepare 5.00 × 102 mL of a 1.75 M H2SO4 solution, starting with an 8.61 M stock solution of H2SO4

We prepare the volume of the 8.61 M stock solution of 0.102 L, then we dilute it by adding water to 0.5 L

Given

5.00 × 10² mL of a 1.75 M H₂SO₄ solution

8.61 M stock solution

Required

The volume of stock solution

Solution

Molarity from 8.61 M to 1.75 M ⇒Dilution

We can use dilution formula :

M₁=8.61 M

V₂=500 ml = 0.5 L

M₂=1.75 M

answer

the ions in solute supperate from eachouthere

they are both synthetic elements

explanation:

d