5gm of hydrogen diffused through a porus membrane in 30 minutes. Find the time required to diffuse
the some amount of so2 gas at identhal conditions.

169.71 minutes

Given

Rate of diffused of Hydrogen=5 gm/30 min

Required

The time required for SO₂

Solution

Graham's law: the rate of effusion of a gas is inversely proportional to the square root of its molar masses or  

the effusion rates of two gases = the square root of the inverse of their molar masses:  

r₁=5gm/30 min

M₁=molar weight of H₂-hydrogen= 2 g/mol

M₂=molar weight of SO₂-sulfur dioxide= 64 g/mol

the time required (for the same amount=5 gm) :

your parents i think this could be it

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.