Show Work 1. If you were to combine hydrogen with 80.0 g of oxygen, how much hydrogen would
you need to completely react with all of the oxygen?

2. Suppose sodium and chlorine form a compound in the ratio of 1.54 g chlorine to
1.0 g sodium. How much sodium would be needed to completely react with 45.0
of chlorine?

Mass of hydrogen needed = 10 g

29.22 gram of sodium are required

Explanation:

1 )Given data:

Mass of oxygen = 80.0 g

Mass of hydrogen needed = ?

Solution:

Chemical equation:

2H₂ +  O₂       →        2H₂O

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles =  80 g/ 32 g/mol

Number of moles = 2.5 mol

now we will compare the moles of oxygen and hydrogen.

               O₂          :         H₂

                 1           :            2

               2.5        :          2× 2.5 = 5 mol

Mass of hydrogen:

Mass = number of moles × molar mass

Mass = 5 mol × 2 g/mol

Mass = 10 g

2 : Given data:

initial mass ration of chlorine and sodium react with each other  = 1.54 g : 1.0 g

Mass of sodium required for 45 g of chlorine = ?

Solution:

                 Cl₂             :          Na

                   1.54          :           1.0

                     45           :          1.0/1.54× 45 = 29.22 g

Thus, 29.22 gram of sodium are required.

idk what the question is about

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.