when 0.15 moles of sodium reacts with 0.30 moles of oxygen what is the moles of the product formed when one reagents is used in excess

0.075 moles of product formed.

Explanation:

Given data:

Number of moles of oxygen = 0.30 mol

Number of moles of oxygen = 0.15 mol

Number of moles of product formed = ?

Solution:

Chemical equation:

4Na + O₂       →    2Na₂O

Now we will compare the moles of Na₂O with oxygen and sodium.

                Na           :           Na₂O

                  4            :              2

                  0.15       :          2/4×0.15 = 0.075 mol

                O₂           :           Na₂O

                  1            :              2

                  0.30       :          2/1×0.30 = 0.6 mol

Less number of moles of Na₂O are produced by sodium thus it will limit the yield of  Na₂O and act as limiting reactant while oxygen is in excess.