You react 14.5 grams of sodium hydroxide with 14.5 grams of copper II sulfate. At the end of the lab you find that you recovered 7.99 grams of precipitate. When you write the balanced equation for you reaction, what is the coefficient in front of sodium hydroxide?

The coefficient  in front of sodium hydroxide is 2.

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.

the balanced reaction between sodium hydroxide and copper (II) sulphate is :

Thus the coefficient  in front of sodium hydroxide is 2.

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

elements make up everything, and they combine to make compounds.

the answer is c