A0.200-kg cube of ice (frozen water) is floating in glycerine. the gylcerine is in a tall cylinder that has inside radius 3.40 cm . the level of the glycerine is well below the top of the cylinder. part aif the ice completely melts, by what distance does the height of liquid in the cylinder change? express your answer with the appropriate units. d =

First, calculate the volume of 0.200 kg of water: d = m/V
d = 1 g/cm^3
m= 200 g

V = m/d = 200 g / 1 g /cm^3 = 200 cm^3

Now, calculate the height of this volumen inside a cylinder with inside radius 3.40 cm

V = π (r^2)*heigth => height = V / [3.1416* (3.40cm)^2]=200 cm^3 / 36.32 cm^2 = 5.51 cm

5.51 cm

The activity series is shown in the attached picture. if the element is below the other, then you can displace the other. following the activity series as a guide, the reactions are as follows: nickel and aluminum chloride3 ni + 2 alcl₃  → 3 nicl₂ + 2 albarium and copper bromideba + cubr  →  no reaction because cu is less oxidizable than bapotassium nitrate and aluminum3 kno₃ + al  → al(no₃)₃ + 3 ksodium phosphate and zincnaso₄ + zn  → znso₄ + na

Okay well gravitational energy is matter forced by gravity making energy though the kinetic energy then the electric energy produces electricity from the kinetic energy and the kinetic energy gets its energy from the gravitational energy. was that the answer you wanted or something else?