A gas occupies 12.3 liters at a pressure of 40.0 mm Hg. What is the volume when the pressure is increased to 60.0 mm Hg? V1 = V2 =
P1 = P2 =
k = k =

Final volume = V₂ =  8.2L

Explanation:

Given data:

Initial volume = 12.3 L

Initial pressure = 40.0 mmHg

Final volume = ?

Final pressure = 60.0 mmHg

Solution:

The given problem will be solved through the Boyle's law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

40.0 mmHg × 12.3 L = 60.0 mmHg × V₂

V₂ = 40.0 mmHg × 12.3 L / 60.0 mmHg

V₂ =  492 mmHg. L /  60.0 mmHg

V₂ =  8.2L

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