A compound is found to consist of 34.5% sodium, 16.4% boron, and 48.6% oxygen. What is the empirical formula? A. NaBO3
B. NaBO2
C. Na2B4O7
D. Na3BO3

The empirical formula is

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given:

Mass of Na= 34.5 g

Mass of B= 16.4 g

Mass of O = 48.6 g

Step 1 : convert given masses into moles.

Moles of Na =

Moles of B =

Moles of O =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For Na =

For B =

For O =

The ratio of Na: B: O= 1: 1: 2

Hence the empirical formula is

true

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