How many moles of oxygen are in a sample of 29.1 moles of coal (C135H96O9NS)?

2.19moles

Explanation:

mole = mass ÷ molar mass

Molar Mass of the compound, C135H96O9NS =

12(135) + 1(96) + 16(9) + 14 + 32

= 1620 + 96 + 144 + 14 + 32

= 1906g/mol

Next, we calculate the mass percent of Oxygen in the compound

O9 = 16(9) = 144g/mol

144/1906 × 100

= 0.0755 × 100

= 7.55%

This means that there are 0.0755g of Oxygen in 1 mole of the coal compound.

Hence, in 29.1 moles of coal, there would be 29.1 × 0.0755

= 2.19moles of Oxygen

i know insulin is primary but i dont know the others im sorry

explanation:

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.