In a 3.7- gram sample, there are atoms of gold

1.1 × 10²² atoms Au

General Formulas and Concepts:

Chemistry

Atomic Structure

Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Math

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right Explanation:

Step 1: Define

3.7 g Au

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of Au - 196.97 g/mol

Step 3: Convert

= 1.13121 × 10²² atoms Au

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

1.13121 × 10²² atoms Au ≈ 1.1 × 10²² atoms Au

Iwould you figure it out but you don't have a picture or in your question as to what the physical property you're looking for is

Maybe you should get some from your teacher and learn more so you can get your grades up and maybe study a bit more