When delta S= 0.218 kj/K, calculate delta G at room temperature (25 Celcius). 2(C3H6) + 9(O2)> 6(CO2) + 6(H2O).

delta H for C3H6 is 20.0 kj/mol, O2 is 0 kj/mol, CO2 is -393.5, H2O is -241.8

Because electrons have negligible mass, to account for the mass of the isotope, there must be 16 neutrons, 16 neutrally charged, massive, fundamental particles present in the sulfur nucleus. and thus finally, if we have the 32s2− ion, there are 18 electrons, 16 protons, and 16 neutrons.

Ijust took the quiz. their is no coefficient needed. : )

Naoh + hbr -> nabr (salt) + h2o ca (oh)2 + 2hbr - - - > ca (br)2 + 2h2o

Hi + naoh -> h2o + nal