g calculate the quantity of energy produced per gram of uranium 235 for the neutron induced Fusion of uranium

Energy released by 1 g of U-235 = 7.603 * 10¹⁰ J

Explanation:

Uranium-235, U-235 undergoes neutron-induced fission to give the following products:

1 neutron + ²³⁵U --> ¹⁴¹Ba + ⁹²Kr + 3 neutrons

Masses of reactants and products:

neutron = 1.009 amu, uranium-235 = 235.044 amu, Ba-141 = 140.910 amu, Kr-92 = 91.910 amu

mass defect = mass of reactants - mass of products

mass defect = (235.044 + 1.009) - (140.910 + 91.910 + 3 * 1.009)

mass defect = 236.053 - 235.847 = 0.206 amu

1 amu = 1.6 * 10⁻²⁷ kg

Using E = mc²

E = 0.206 * 1.6* 10⁻²⁷ kg * (3 * 10⁸ m/s)² = 2.966 * 10⁻¹¹ J

therefore, 1 atom of U-235 releases 2.966 * 10⁻¹¹ J of energy

energy released by 1 g of U-235 can be calculated as follows:

1 mole or 253 g  of U-235 contains 6.02 * 10³ atoms

1 g of U-235 will contain 6.02 * 10³/235 = 2.563 * 10²¹ atoms

Energy released by 1 g of U-235 = 2.563 * 10²¹ * 2.966 * 10⁻¹¹ J = 7.603 * 10¹⁰ J

1.solid

2.carbon dioxide

3.helium

i'm pretty sure its b i might be wrong though!