A sample of gas in a balloon has an initial temperature of 42 ∘C and a volume of 1.10×103 L . If the temperature changes to 86 ∘C , and there is no change of pressure or amount of gas, what is the new volume, V2, of the gas?

1250L or 1.25*10^3

Explanation:

Use the combined gas law, =

Put the value for the temperature(in Kelvin) and volume, and you can just put 1 for P1 and P2 because it stays the same.

I'll assume that you meant to put 1.10*10^3L

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.