How many grams do you have in: 5.3 moles of Zr(NO3)4

1800 g Zr(NO₃)₄

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

5.3 mol Zr(NO₃)₄

Step 2: Identify Conversions

Molar Mass of Zr - 91.22 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Zr(NO₃)₄ - 91.22 + 4(14.01) + 12(16.00) = 338.26 g/mol

Step 3: Convert

= 1798.08 g Zr(NO₃)₄

Step 4: Check

We are given 2 sig figs. Follow sig fig rules and round.

1798.08 g Zr(NO₃)₄ ≈ 1800 g Zr(NO₃)₄

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.

o conteúdo de calor de um sistema é igual à entalpia apenas para um sistema que é constante