This table shows the densities of a sample of substances. Substance
A
B
с
D
E
Density (g/cm)
0.99
0.70
1.32
0.57
1.12
Which correctly describes how these substances would be arranged in a beaker from bottom to top given their
densities?
O A, B, C, D, E
O E, D, C, B, A
O C, E, A, B, D
OD, B, A, E, C

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.

I'm pretty sure its c

Heat capacity = mcδtheat capacity = 2.676×10^3 j ..the heat capacity given is for 7.00 g of kcn,potassium cyanide which is equal to 0. mole of mole = mass  ÷ mr of kcn is 7  ÷ 65 =0.therefore: 0. of kcn liberates 2.676×10^3 j of heat1 mole   (2.676×10^3    ÷  0.107 )  × 1 =do the calculation to obtain 25009 j = 25kj