How much heat is required to take a 150 g sample of water from 10.0 ℃ to 95.0 ℃? cs, water = 4.184 J/g*℃

Explanation:

We are given the specific heat and change in temperature, so we should use this heat formula:

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

We know the mass is 150 grams. The specific heat of water is 4.184 J/g °C.

Let's find the change in temperature.

Subtract the initial temperature from the final temperature.

Now we know all the values:

Substitute them into the formula.

Multiply all three numbers together. Note that the grams (g) and degrees Celsius (°C) will cancel out. Joules (J) will be the only remaining unit.

53,346 Joules of heat are required.

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