For the following reaction, calculate how many moles of each product are formed when 4.05 g of water is used. 2H20 →2H2 + O2

0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.

Explanation:

The given reaction is

2 moles of is used to form 2 moles of and 1 mole of

As 1 mole of , 1 mole of , and 1 mole of .

So, 36 grams of is used to form 4 grams of and 32 grams of

Therefore, 1 gram of is used to form 4/36 grams of and 32/36 grams of

Therefore, 4.05 gram of is used to form (1/9)4.09=0.45 grams of and (8/9)4.05=3.53 grams of .

Hence, 0.45 grams of hydrogen and 3.53 grams of oxygen will be formed, when 4.05 grams of water is used.

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )