At 35°C and 2 atm of pressure, the volume of gas is 200 ml. If the temperature changes to 55°C and the pressure changes to 4 atm, what is the new volume of gas?

V₂ = 106.5 mL

Explanation:

Given data:

Initial volume =200 mL

Initial pressure = 2 atm

Initial temperature = 35 °C (35 +273 = 308 K)

Final temperature = 55°C (55+273 = 328 K)

Final volume = ?

Final pressure = 4 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 2 atm ×200 mL × 328 K / 308 K ×4 atm

V₂ = 131200 atm .mL. K / 1232 K.atm

V₂ = 106.5 mL

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