Question 15 (1 point) When a toy car is wound up and released on a tile floor, It accelerates as shown in the diagram. What is the force in Newtons that the car's
wheels exert on the floor when it is released?
Acceleration = 0.5 m/s2
Mass = 1.0 kg
Оа
Ob
Ос
Od
0.05N
0.5 N
SN
50 N

Option B. 0.5 N.

Explanation:

Data obtained from the question include:

Mass (m) = 1 Kg

Acceleration (a) = 0.5 m/s²

Force (F) =?

Force is defined as the product of mass (m) and acceleration (a). Mathematically, it is expressed as:

Force (F) = mass (m) × acceleration (a)

F = ma

Using the above equation, we can obtain the force exerted on the floor as follow:

Mass (m) = 1 Kg

Acceleration (a) = 0.5 m/s²

Force (F) =?

F = ma

F = 1 × 0.5

F = 0.5 N

Thus, the car exerted a force of 0.5 N on the floor.

it should be p1 v1 = p2 v2