a solution of AICI is combined with a solution of KOH. Identify the precipitate and the spectator ions in the resulting reactions.

The  the precipitate : Al(OH)₃(s)

The spectator ions : 3Cl⁻ and 3K⁺

Reaction

AlCl₃ + 3KOH → Al(OH)₃ + 3KCl

From solubility rules :

Compounds of OH− are insoluble except Compounds of Li +, Na +, K +, Rb +, Cs +, NH₄⁺ , Sr²⁺, and Ba²⁺

Compounds of Cl−, Br−, I− are soluble except Ag⁺, Hg₂²⁺, Pb²⁺

So the  the precipitate : Al(OH)₃(s)

net ionic reaction

AlCl₃ + 3KOH → Al(OH)₃ + 3KCl

Al³⁻+3Cl⁻+3K⁺+3OH⁻⇒Al(OH)₃(s)+3K⁺+3Cl⁻

Remove the spectator : 3Cl⁻ and 3K⁺

Al³⁻(aq)+3OH⁻(aq)⇒Al(OH)₃(s)

може ли да зареждате повече информация, моля

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.