ATOMIC MATH
Solve the problem as we did in class, starting each step with the answer from the previous step.
NO DECIMALS; NO NEGATIVE NUMBERS
Add the atomic number of radium, Ra, to the number of electrons in argon 1 point
Ar.
Your answer
Subtract the atomic mass (rounded) of sodium, Na.*
1 point
Your answer
Multiply by the number of protons in beryllium, Be
1 point
Your answer
Divide by the number of electrons in helium, He.
1 point
Your answer
Subtract the number of neutrons in iron, Fe,
1 point
Your answer
Answers: 1
Chemistry, 22.06.2019 07:30
The table compares the number of electrons in two unknown neutral atoms. comparison of electrons atom number of electrons a 10 d 11 use this information to determine the number of valence electrons in the atoms. which of the following correctly compares the stability of the two atoms? both are unreactive. both are highly reactive. a is unreactive and d is reactive. a is reactive and d is unreactive.
Answers: 3
Chemistry, 22.06.2019 14:30
What type(s) of intermolecular forces are expected between ch3ch2cooh molecules? dipole forces, induced dipole forces, hydrogen bonding
Answers: 1
Chemistry, 22.06.2019 19:00
Mercury metal is poured into a graduated cylinder that holds exactly 22.5 ml the mercury used to fill the cylinder mass in 306.0 g from this information calculate the density of mercury
Answers: 2
Chemistry, 22.06.2019 22:40
Percent ionization for a weak acid (ha) is determined by the following formula: percent ionization=[ha] ionized[ha] initial×100%for strong acids, ionization is nearly complete (100%) at most concentrations. however, for weak acids, the percent ionization changes significantly with concentration. the more diluted the acid is, the greater percent ionization.a certain weak acid, ha, has a ka value of 9.4×10? 7.part acalculate the percent ionization of ha in a 0.10 m solution.part bcalculate the percent ionization of ha in a 0.010 m solution
Answers: 1
ATOMIC MATH
Solve the problem as we did in class, starting each step with the answer from the previ...
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