WILL GIVE BRAINLIEST Calculate the volume of 18.0 M H2SO4 needed to prepare 500.0 mL of 2.00 M H2SO4.

ust use the equation

M1 X V1 = M2 X V2

where M1 is the initial concentration, V1 the volume of M1, M2 the final concentration and V2 the final volume. Here you are looking for V1 so, first solve for V1 and put in the numbers.

V1 = (M2 X V2)/M1 = (3 X 0.5)/18 = 0.5/6 = 0.083 L or 83 mL

Explanation:

pls make me brainliest

V₁  = 55.55 mL

Explanation:

Given data:

Initial volume V₁ = ?

Initial molarity M₁ = 18.0 M

Final volume V₂= 500.0 mL

Final molarity M₂= 2.00 M

Solution:

Formula:

M₁V₁   =   M₂V₂

V₁  = M₂V₂ /M₁

By putting values,

V₁  =  2.00 M × 500.0 mL/ 18.0 M

V₁  = 1000 M.mL /18.0 M

V₁  = 55.55 mL

fe 55.85 g/mol and h2o 18.02 g/mol.