A 1000-g iron frying pan is placed on a stove. The pan increases from 20°C to 130°C. If the specific heat of iron is 0.444 J/goC, how much heat was gained by the pan? A. -48,840 J
B. 48,840 J
C. 57,720 J
D. - 57,720 J

48,840 J

Explanation:

First of all, you can use process of elimination to take out the negatives, since you can't gain negative heat (in this situation).

Now just for the Math:

Remember this equation — Q = mcΔt

The variables for the equation are:

— m - The measure in grams or kilograms.

— c - The measure of the specific heat.

— Δt - The measure the change in temperature.

Now find these variables:

— m = 1000 g

— c = 0.444 J/goC

— Δt = 130 - 20 = 110 C

Now plug these numbers into the equation and solve!

Q = mcΔt

If you multiply the number you would get 48,840 J. You also have to cancel out the units as well.

Hope it Helped!

Pls Give Brainliest!

just did the assignment and the answer was #1 +2 n