Given that the molar mass of nacl is 58.44 g/mol, solve for the molarity of a solution that contains 87.75 g of nacl in 500 ml of solution.

a.) 0.333 m
b.) 0.751 m
c.) 1.50 m
d.) 3.00 m

Grams/Molar Mass = Moles 

Molarity = Moles/Liters

The above formulas are important for solving this problem.

Number of moles of Nacl = 87.75/58.44

                                         = 1.50

Molarity = Number of moles of solute (here NaCl) / Volume of solution in Liters

Then

Volume of solution in Liters = Number of moles of solute (here NaCl)/Molarity

Volume of solution in Liters = 500/1500

                                            = 0.333 M

The correct option among all the options that are given in the question is the first option or option "A".

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